Postcard from Fritz Haber to Georg Bredig, January 1900
- 1900-Jan-18
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Small JPG1200 x 813px — 154 KBLarge JPG2880 x 1951px — 739 KBFull-sized JPG3516 x 2382px — 1.0 MBOriginal fileTIFF — 3516 x 2382px — 24.0 MBIn a postcard to Georg Bredig (1868-1944), Fritz Haber (1868-1934), a German chemist who received the Nobel Prize in Chemistry in 1918 for his invention of the Haber–Bosch process, discusses the platinum potentials of platinized gold.
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Haber, Fritz. “Postcard from Fritz Haber to Georg Bredig, January 1900,” January 18, 1900. Papers of Georg and Max Bredig, Box 1, Folder 49. Science History Institute. Philadelphia. https://digital.sciencehistory.org/works/jbpzyuo.
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Image 1
Deutsche Reichspost
Postkarte
Dr. Fritz Haber
Privatdozen a.d. Tech. Hochschule Karlsruhe.
Herrn Dr. Georg Bredig
Leipzig
Lennéstr. 2/3
Physicalisch Chemisches Institut
Image 2
18.I.1900
Lieber Freund!
Erinnerst du dich was wir in Leipzig über die Platin-potentiale lernten? Deine sehr schöne Arbeit habe ich inzwischen gelesen und meine daheim wieder weiter verfolgt. Wahrlich die Natur ist einfacher als die Phantasie. Die Platinpotentiale in Gegenwart von H2O2 sind bei platiniertem Gold wo Platin als Diffusionsgeber entfällt so viel ich bislang sehe gerade auf E = k lg 1/CH2O2 – const.
Die potentialbestimmende Sauerstoffconcentration in der Platinoberfläche ist also im Gleichgewicht mit H2O2 CH2O2 · CO = k · CH2O · CO2 bei constanter rechten Seite.
Was machst du sonst?
Herzl. Gruß
Dein F. Haber
Image 1
German Imperial Postal Service
Postcard
Dr. Fritz Haber
Lecturer at the Technical University of Karlsruhe
Dr. Georg Bredig
Leipzig
Lennéstr. 2/3
Physical Chemistry Institute
Image 2
January 18, 1900
Dear Friend,
Do you remember what we learned in Leipzig about platinum potentials? I have read your interesting work in the meantime and continued to work on mine at home. Nature is truly simpler than imagination. Platinum potentials in the presence of H2O2 occur with platinized gold, where platinum is not used as a diffusion agent, especially when I consider the E = k lg 1/CH2O2 – constant.
The potential-determining oxygen concentration in the platinum surface is therefore in equilibrium with H2O2 CH2O2 CO = k CH2O CO2 with a constant right-hand side.
What else are you doing?
Warm regards,
F. Haber
